Empty trigs are steps that aren’t lit up red. After I record the filter sweep, the empty (not lit up) trigs turn yellow, the yellow trigs now have a filter lock and the unwanted note data “0” added were there was no note before. It changes the pitch of the release on the 1/8 beat melody I recorded.
“Do you mean the lock trigs have a note of zero ? If so, does this fall into the non-locked defaults that I discussed above, in this case it is not a lock nor significant and nor should it change pitch”
If the pitch of the prior step is “2” and not this non-locked default is “0” it changes the pitch from the prior step when the amp release carries over to the non-locked “0” default pitch.
“I also tried what you wrote, those steps are too vague tbh, but I don’t see pitch changes.”
Sorry, let me try again:
Start with a blank pattern
Set track 1 machine to Dual VCO and chromatic mode
Hit live record and play a melody with an 1/8th beat pattern. Note trigs will fall on steps 1, 3, 5, 7… etc
Now, live record a filter cutoff sweep over that melody/pattern
Disengage live recording.
My result is the filter cutoff sweep is recorded over the pattern but the steps between the note trigs (steps 2, 4, 6, 8… etc) have a note value of “0” which can be heard in the amp envelope release of the recorded melody on steps 1, 3, 5… etc etc.